|
|
One thousand kilograms per hour of a mixture of benzene (B) and toluene(T) that contains 50% benzene by mass are seperated by distillation into two fractions. The mass flow rate of benzene in the top stream is 450 kg B/h, and that of toluene in the bottom stream is 475 kg T/h. The operation is at steady state. Write balances on benzene and toluene to calculate the unknown component flow rates in the output streams. Ftotal, toluene = Fbottoms, toluene + Fbottoms,toluene 500 = Foverhead, toluene + 475 Foverhead, toluene = 500 - 475 = 25 kg/h. We now know everything that we can know about this process. We must be able to answer any of the questions that they ask us.
|
© 2007 Arizona Board of Regents for The University of Arizona |