One thousand kilograms per hour of a mixture of benzene (B) and toluene(T) that contains 50% benzene by mass are seperated by distillation into two fractions. The mass flow rate of benzene in the top stream is 450 kg B/h, and that  of toluene in the bottom stream is 475 kg T/h.  The operation is at steady state.  Write balances on benzene and toluene to calculate the unknown component flow rates in the output streams.

Ftotal, toluene = Fbottoms, toluene + Fbottoms,toluene

500 = Foverhead, toluene + 475

Foverhead, toluene = 500 - 475 = 25 kg/h.

We now know everything that we can know about this process. We must be able to answer any of the questions that they ask us.

Streams\mass flow rate Total Benzene Toluene
Feed 1000 500 500
Overhead 475 450 25
Bottoms 525 50 475



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