One thousand kilograms per hour of a mixture of benzene (B) and toluene(T) that contains 50% benzene by mass are seperated by distillation into two fractions. The mass flow rate of benzene in the top stream is 450 kg B/h, and that  of toluene in the bottom stream is 475 kg T/h.  The operation is at steady state.  Write balances on benzene and toluene to calculate the unknown component flow rates in the output streams.

Ftotal = Fbottoms + Fbottoms

1000 = Fbottoms + 525

Fbottoms = 1000 - 525 = 475 kg/h.

Streams\mass flow rate Total Benzene Toluene
Feed 1000 500 500
Overhead 475 450
Bottoms 525 50 475

Now, only one equation to go!

Ftotal, toluene = Foverhead, toluene + Fbottoms,toluene

Where should we click next to use this last equation? (Only one choice here!)




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